For any real numbers \(a\), \(b\), and \(c\)

$$\left( {a \times b} \right) \times c = a \times \left( {b \times c} \right)$$

If you **multiply** three numbers together, the **product** will be the same no matter how you group the numbers.

Suppose, we are given the following values

$$\displaylines{

a = 4 \cr

b = 2 \cr

c = 7 \cr} $$

We plug them into the "formula"

$$\left( {a \times b} \right) \times c = a \times \left( {b \times c} \right)$$

We have

$$\displaylines{

\left( {4 \times 2} \right) \times 7 = 4 \times \left( {2 \times 7} \right) \cr

8 \times 7 = 4 \times 14 \cr

56 = 56 \cr} $$

Great! The left side and the right side of the equation do have the same result. They have the same product of \(56\).